Question

A stunt man is being pulled, at a constant velocity, along a rough road by a cable attached to a truck. The cable is parallel to the ground. The mass of the stunt man is 109 kg, and the coefficient of kinetic friction between the road and the stunt man is 0.870. Find the tension in the cable.

Answer 1

Step-by-step explanation:

Below is an attachment containing the solution.

Answer 2

the tension in the cable= 929.33N

Step-by-step explanation:

the tension in the cable is equivalent to the frictional force experienced between the road and the stunt man

coefficient of friction= μ=
`(F_(r) )/(N)`

μ=0.870

N= Normal force =m × g

m= 109kg

g= acceleration due to gravity =9.8m/s²

`F_(r)`= μ × N

`F_(r)`= μ × m × g

`F_(r)`= 0.870 × 109 × 9.8

`F_(r)`=929.33N

The tension in the cable is 929.33N