Question

A sample of oxygen gas at 25.0°c has its pressure tripled while its volume is halved. What is the final temperature of the gas?

Answer 1

Step-by-step explanation:

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Answer 2

447 K

Step-by-step explanation:

25 C = 25 + 273 = 298 K

Assuming ideal gas, we can apply the ideal gas law

`(P_1V_1)/(T_1) = (P_2V_2)/(T_2)`

`T_2 = T_1(P_2)/(P_1)(V_2)/(V_1)`

Since pressure is tripled, then
`P_2 / P_1 = 3`. Volume is halved, then
`V_2 / V_1 = 0.5`

`T_2 = 298*3*0.5 = 447 K`