Question

Calculate the equilibrium constant for the reaction below given that [Cl2] = 0.21 M, [H2] = 0.13 M, and [HCl] = 0.95 M at equilibrium. Given: Cl2(g) + H2(g) ⇌ 2HCl(g)

Answer 1

The equilibrium constant for this reaction is 33

Step-by-step explanation:

Step 1: Data given

[Cl2] = 0.21 M

[H2] = 0.13 M

[HCl] = 0.95 M

Step 2: The balanced equation

Cl2(g) + H2(g) ⇌ 2HCl(g)

Step 3: Calculate the equilibrium constant

K = [HCl]² / [Cl2][H2]

K = [0.95]² /[0.21][0.13]

K = 33.06 ≈ 33

The equilibrium constant for this reaction is 33

Answer 2

The answer to your question is Ke = 33.06

Step-by-step explanation:

Data

[Cl₂] = 0.21 M

[H₂] = 0.13 M

[HCl] = 0.95 M

Balanced chemical reaction

Cl₂(g) + H₂(g) ⇔ 2HCl (g)

Formula

Ke =
`\frac{[HCl]^(2)}{[Cl_{2][H_(2)]}}`

Substitution

Ke = [0.95]² / [0.21][0.13]

Simplification

Ke = 0.9025 / 0.0273

Result

Ke = 33.06

The equilibrium constant does not have units.