Question

PLEASE HELP ME!!!!!!!!

A composite figure is divided into two congruent trapezoids, each with a height of 4 cm.

2 trapezoids. Both trapezoids have base lengths of 10 centimeters and 6 centimeters, and a height of 4 centimeters.
Trapezoid area: A = one-half (b 1 + b 2) h

What is the area of this composite figure?
32 centimeters squared
40 centimeters squared
64 centimeters squared
80 centimeters squared

Answer 1

Option C:
`64 \ cm^2` is the area of the composite figure.

Step-by-step explanation:

It is given that the composite figure is divided into two congruent trapezoids.

The measurements of both the trapezoids are

`b_1=10 \ cm`

`b_2=6 \ cm` and

`h=4 \ cm`

Area of the trapezoid =
`(1)/(2) (b_1+b_2)h`

Substituting the values, we get,

`A=(1)/(2) (10+6)4`

`A=(1)/(2) (16)4`

`A=32 \ cm^2`

Thus, the area of one trapezoid is
`$32 \ {cm}^(2)$`

The area of the composite figure can be determined by adding the area of the two trapezoids.

Thus, we have,

Area of the composite figure = Area of the trapezoid + Area of the trapezoid.

Area of the composite figure =
`$32 \ {cm}^(2)+32 \ {cm}^(2)$`
`= 64 \ cm^2`

Thus, the area of the composite figure is
`64 \ cm^2`

Hence, Option C is the correct answer.