Answer:
2x-z=0 is the equation of the plane.
Explanation:
Given that the plane passes through the points (1,0,2) and (-1,1,-2)
and also origin.
Hence equation of the plane passing through three points we can use
Any plane passing through 3 given points is given as
![\left[\begin{array}{ccc}x-x_1&y-y_1&z-z_1\\x_2-x_1&y_2-y_1&z_2-z_1\\x_3-x_1&y_3-y_1&z_3-z_1\end{array}\right] =0](https://img.qammunity.org/2021/formulas/mathematics/college/6zvdthz8qujyexdwggzg3umrpe9q4dx7x3.png)
Substitute the three points to get
![\left[\begin{array}{ccc}x-1&y&z-2\\-1-1&1&-2-2\\0-1&0&0-2\end{array}\right] \\=0\\(x-1)(-2) -y(4-4)+(z-2)(1) =0\\-2x+z=0\\2x-z-=0](https://img.qammunity.org/2021/formulas/mathematics/college/ibqmbgyvffa2gjdrrp7rxct7tw6f18f5c0.png)
2x-z=0 is the equation of the plane.