Question

Joan needs a 0.053-M solution of HCl, but only has access to 2.12-M HCl, a 10-mL graduated pipet, and a 25-mL volumetric flask. How much HCl should she measure to create her desired solution

Answer 1

Joan should measure 0.625 mL of 2,12 M HCl solution to create her desired solution.

Step-by-step explanation:

Molarity of HCl Joan has access to =
`M_1=2.12 M`

Volume of 2.12 M of HCl Joan use =
`V_1=?`

Molarity of HCl Joan desired =
`M_2=0.053 M`

Volume of 0.053 M of HCl Joan can prepare =
`V_2=25 mL`

`M_1V_1=M_2V_2`

`V_1=(M_2V_2)/(M_1)`

`=(0.053 M* 25 mL)/(2.12 M)=0.625 mL`

Joan should measure 0.625 mL of 2,12 M HCl solution to create her desired solution.