Answer:
Explanation:
in this case, x = the number of success in 3 trials, so x is a binomial distributed random variable, hence:
P(x=0) = (3C0)*(0.11)^0*(1-0.11)^(3-0)=0.704969
P(x=1) = (3C1)*(0.11)^1*(1-0.11)^(3-1) = 0.261393
P(x=2) = (3C2)*(0.11)^2*(1-0.11)^(3-2)= 0.032307
P(x=3) = (3C3)*(0.11)^3*(1-0.11)^(3-3)= 0.001331
E(x) = n*p = 3*0.11=0.33
σ =
(n*p*(1-p)=0.542
E(y) = n*p = 1700*0.11=187