Question

Consider a thermal energy reservoir at 1500 K that can supply heat at a rate of 150,000 kJ/h. Determine the exergy of this supplied energy, assuming an environment temperature of 25°C.

Answer 1

exergy = 33.39 kW

Step-by-step explanation:

given data

thermal energy reservoir T2 = 1500 K

heat at a rate = 150,000 kJ/h =
`(15000)/(3600)` kW = 41.67 kW

environment temperature T1 = 25°C = 298 K

solution

we get here maximum efficiency that is reversible efficiency is express as

reversible efficiency = 1 -
`(T1)/(T2)` ...............1

reversible efficiency = 1 -
`(298)/(1500)`

reversible efficiency = 0.80133

and

the exergy of this supplied energy that is

exergy = efficiency × hat supply ................2

exergy = 0.80133 × 41.67 kW

exergy = 33.39 kW