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Express the complex number in trigonometric form.
4i

1 Answer

6 votes

Question: Express
4i in trigonometric form.

Answer:

A few ways to express this is:


4(\cos((\pi)/(2))+\sin((\pi)/(2))i)


4cis((\pi)/(2))


4e^{i(\pi)/(2)}

Choose the notation your class is using.

Explanation:


r(\cos(\theta)+\sin(\theta)i) is trigonometric form.

Distributing
r to terms inside the ( ) gives:


r\cos(\theta)+r\sin(\theta)i.

Our number has no real part so we are just trying to find
r and
\theta such that
r\sin(\theta)=4.

Since we want
\cos(\theta)=0, we will have to
\sin(\theta)=1 (or -1).

This happens at
(\pi)/(2).

This means
\theta=(\pi)/(2).

So while
\sin(\theta)=1 this forces
r=4

The trigonometric form is
4(\cos((\pi)/(2))+\sin((\pi)/(2))i).

Some people like to express this as
4cis((\pi)/(2)) which is way shorter.

Some people might also express this as
4e^{i(\pi)/(2)}.

User Vanitas
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