Answer:
2 window air-conditioning units are required.
Step-by-step explanation:
Rate of heat transfer by a person at rest = 360 kJ/h = 360 kJ/h × 1 h/3600 s = 0.1 kW
Assuming the 40 people in the classroom are at rest.
Rate of heat transfer of 40 people at rest = 40×0.1 = 4 kW
Rate of heat transfer by 1 lightbulb = 100 W = 100/1000 = 0.1 kW
Rate of heat transfer by 11 lightbulbs = 11×0.1 = 1.1 kW
Rate of heat transfer to the classroom through the walls and windows = 15000 kJ/h = 15000 kJ/h × 1 h/3600 s = 4.167 kW
Total heat transfer = 4 + 1.1 + 4.167 = 9.267 kW
Cooling capacity of a window air-conditioning unit = 5 kW
Number of air-conditioning units required = 9.267/5 = 2 (to the nearest integer)