Question

write the standard form of the equation of the circle with the given center and radius (6,4), r= square root of 7

Answer 1

The standard form of the equation of a circle is
`(x-6)^(2)+(y-4)^(2)=7`.

Solution:

Center of the circle = (6, 4)

Radius of the circle =
`√(7)`

To find the equation of the circle:

General formula for the equation of a circle

`(x-h)^(2)+(y-k)^(2)=r^(2)`

where (h, k) is the center of the circle and r is the radius of the circle.

Here, h = 6, k = 4 and r =
`√(7)`

`(x-6)^(2)+(y-4)^(2)=(√(7)) ^(2)`

`(x-6)^(2)+(y-4)^(2)=7`

Hence the standard form of the equation of a circle is
`(x-6)^(2)+(y-4)^(2)=7`.