Question

A circus performer stretches a tightrope between two towers. He strikes one end of the rope and sends a wave along it toward the other tower. He notes that it takes the wave 0.775 s to reach the opposite tower, 20.0 m away. If a 1 meter length of the rope has a mass of 0.300 kg, find the tension in the tightrope. N

Answer 1

Step-by-step explanation:

The given data is as follows.

Distance (s) = 20 m

time (t) = 0.775 s

Also, it is given that mass per 1 meter length (m) = 0.300 kg

Formula to calculate the velocity is as follows.

Velocity (v) =
`(s)/(t)`

Putting the given values into the above formula as follows.

v =
`(s)/(t)`

=
`(20 m)/(0.775 s)`

= 25.80 m/s

We know that,

v =
`\sqrt{(T)/(m)}`

Taking square on both the sides, the formula will become as follows.

T =
`mv^(2)`

=
`0.3 kg * 25.80`

= 199.692 N

Therefore, we can conclude that tension in the given tightrope is equal to 199.692 N .