Question

Here's a graph of a linear function. Write the equation that describes that function.

Express it in slope-intercept form.

Answer 1

Answer:w t f

Explanation:

Answer 2

Answer:

The equation of the line is 3y=x-12

Explanation:

This is a straight line graph.

And general equation of a straight is given by

y=mx+c

Where m is slope

c is the intercept on y axis at x=0

So at y=-2, x=6 This is from the graph.

And inserting this value of y and x into the straight line equation

y=mx+c

-2=6m+c

Therefore, c=-2-6m. Equation 1

Taking another point on the graph

at=0, y=-4

Also, inserting this value of y and x into the straight line equation

-4=0×x+c

-4=0+c

Therefore, c=-4.

Therefore the intercept is -4

From equation 1

c=-2-6m c=-4

-4=-2-6m

-4+2=-6m

-2=-6m

m=-2/-6

m=1/3

Then the equations of then line is

y=mx+c

y=(1/3)x-4

Multiply through by 3

3y=x-12

The equation of the line is 3y=x-12