200k views
5 votes
Suppose the coefficient of static friction between the road and the tires on a car is 0.60 and the car has no negative lift. What speed will put the car on the verge of sliding as it rounds a level curve of 34.0 m radius?

2 Answers

2 votes

Answer:

Speed = 14.15 m/s.

Step-by-step explanation:

Below is an attachment containing the solution.

Suppose the coefficient of static friction between the road and the tires on a car-example-1
User Lord Null
by
4.9k points
3 votes

Answer:

14.139m/s

Step-by-step explanation:

For a body moving along a curve on a surface whose coefficient of friction is
\mu, the maximum velocity v the body can sustain beyond which it would skid off is given by equation (1);


v=√(\mu gR)............(1)

where g is acceleration due to gravity taken as
9.8m/s^2 and R is the radius of the curve.

Given;


\mu=0.6\\R=34m

Hence'


v=√(0.6*9.8*34) \\v=√(199.92)\\ v=14.139m/s

User Kennon
by
4.9k points