Answer:
14.139m/s
Step-by-step explanation:
For a body moving along a curve on a surface whose coefficient of friction is
, the maximum velocity v the body can sustain beyond which it would skid off is given by equation (1);
![v=√(\mu gR)............(1)](https://img.qammunity.org/2021/formulas/physics/high-school/p7cjq3lxjlaqkintwkd589o5huu9tiypr6.png)
where g is acceleration due to gravity taken as
and R is the radius of the curve.
Given;
![\mu=0.6\\R=34m](https://img.qammunity.org/2021/formulas/physics/high-school/sdhikjsz2lmy6dutoj38xrxh4ubhcafziw.png)
Hence'
![v=√(0.6*9.8*34) \\v=√(199.92)\\ v=14.139m/s](https://img.qammunity.org/2021/formulas/physics/high-school/hqun205p7k9hqt67g7btukk89cuyqhzxuh.png)