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Determine whether
f(x)=(1)/(2)x^(2)-x-9 has a maximum or a minimum value and find that value.

1 Answer

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First of all, recall that every parabola can be written as


y=ax^2+bx+c,\quad a\\eq 0, b \in \mathbb{R}, c \in \mathbb{R}

If
a>0, the parabola is concave up (and thus it has a minimum value).

If
a<0, the parabola is concave down (and thus it has a maximum value).

So, in your case, the parabola in concave up.

The x-coordinate of the minimum can be found using


x=-(b)/(2a)=-(-1)/(1)=1

And the y-coordinate will be


f(1)=(1)/(2)(1)^2-1-9 = -(19)/(2)

So, the minimum value is -19/2 at x=1.

User Diony
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