Question

Find the distance between points P(1,2) and Q(4,8) to the nearest tenth.

A. 5
B. 6.7
C. 11.2
D. 9

Answer 1

B. 6.7

Explanation:

`\sqrt{(x_(2)-x_(1))^(2) +(y_(2)-y_(1))^(2) }`

`\sqrt{(1-4)^(2) +(2-8)^(2) }`

`\sqrt{(-3)^(2) +(-6)^(2) }`

`√(9 +36 )`

`√(45 )`

`3√(5)`

Then plug-in calculator

6.70820393...

Answer 2

the answer will be option B 6.7

Step-by-step explanation: in co-ordinate geometry, let the P(x1, y1) and Q(x2, y2) be two points.

so their distance will be = sqaure root of ((x1 - x2)^2+(y1 - y2)^2)

here we take x1 = 1 , y1 = 2

and x2 = 4 , y2 = 8

so putting the values in the equation we get,

`√((1-4)^2 + (2 - 8)^2)`

=
`√((-3)^2+(-6)^2)`

=
`√(9+36)`

=
`√(45)`

=6.70820393