Amount of heat energy required by water is 251100 J
Amount of energy required by iron is 4500 J
Step-by-step explanation:
The heat required to raise the temperature of 2kg water at 30 degrees:
Q= mcΔT (C= specific heat, ΔT change in temperature, m mass of the substance)
The specific heat capacity of water is given as 4.184
the specific heat capacity of iron is given as 0.45 AT 25 DEGREES
Q= 2 *1000*0.450*5 as (ΔT= 30-25)
= 4500 J
Heat required by 2kg iron at 30 degrees
Q= 2*1000*4.184* 30
= 251100 joules