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I need help with the follow question.

Find the solution for this system of equations.

2x + 4y = 8
x = 3y − 6

1 Answer

3 votes

Answer:


x=0,y=2

Explanation:

Given equation:


2x + 4y = 8 Equation:1


x = 3y-6\\or\\x-3y=-6 Equation:2

Multiplying equation:2 by 2 gives:


2x-6y=-12 Equation:3

Subtracting Equation:3 from Equation:1


2x + 4y-(2x-6y) = 8-(-12)

The negative sign outside the bracket changes the sign inside it after opening the bracket


2x+4y-2x+6y=8+12


10y=20\\\\y=2

Putting the value of 'y' in Equation:2


x-3y=-6\\x-3(2)=-6\\x-6=-6\\x=-6+6\\x=0


x=0,y=2

User TheLukeMcCarthy
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