Question

I need help with the follow question.

Find the solution for this system of equations.

2x + 4y = 8
x = 3y − 6

Answer 1

`x=0,y=2`

Explanation:

Given equation:

`2x + 4y = 8` Equation:1

`x = 3y-6\\or\\x-3y=-6` Equation:2

Multiplying equation:2 by 2 gives:

`2x-6y=-12` Equation:3

Subtracting Equation:3 from Equation:1

`2x + 4y-(2x-6y) = 8-(-12)`

The negative sign outside the bracket changes the sign inside it after opening the bracket

`2x+4y-2x+6y=8+12`

`10y=20\\\\y=2`

Putting the value of 'y' in Equation:2

`x-3y=-6\\x-3(2)=-6\\x-6=-6\\x=-6+6\\x=0`

`x=0,y=2`