Question

Nitrous oxide, N 2 O , has a mass ratio of nitrogen to oxygen of 1.00 : 0.57 . Determine the ratio by mass of nitrogen to oxygen in dinitrogen trioxide, N 2 O 3 , and dinitrogen pentoxide, N 2 O 5 . N 2 O 3 has a mass ratio of nitrogen to oxygen of 1.00 : N 2 O 5 has a mass ratio of nitrogen to oxygen of 1.00 :

Answer 1

`\large\boxed{N_2O_3\text{ has a mass ratio of nitrogen to oxygen of }1.00:1.71}`

`\large\boxed{N_2O_5\text{ has a mass ratio of nitrogen to oxygen of }1.00:2.85}`

Step-by-step explanation:

1.
`N_2O`

Mass ratio: 1.00 : 0.57 (given)

Represent the atomic mass of N by x and the atomic mass of O by y, then:

`(2x)/y=1/0.57\\\\x/y=1/(2* 0.57)=1/1.14`

2.
`N_2O_3`

Using x and y for the corresponding atomic masses, the mass ratio of
`N_2O_3` is:

`mass\text{ }ratio=(2x)/(3y)`

Use x/y = 1/1.14

`mass\text{ }ratio=2x/(3y)=(2/3)(1/1.14)=2/3.42`

Divide both numerator and denominator by 2:

`mass\text{ }ratio=1.00/1.71`

`\large\boxed{N_2O_3\text{ has a mass ratio of nitrogen to oxygen of }1.00:1.71}`

3.
`N_2O_5`

Using x and y for the corresponding atomic masses, the mass ratio of
`N_2O_5` is:

`mass\text{ }ratio=(2x)/(5y)`

Use x/y = 1/1.14

`mass\text{ }ratio=(2x)/(5y)=(2/5)(1/1.14)=2/5.7`

Divide both numerator and denominator by 2:

`mass\text{ }ratio=1.00/2.85`

`\large\boxed{N_2O_5\text{ has a mass ratio of nitrogen to oxygen of }1.00:2.85}`