224k views
5 votes
Air in a 10 ft3 cylinder is initially at a pressure of 10 atm and a temperature of 330 K. The cylinder is to be emptied by opening a valve, and letting the pressure drop to that of the atmosphere. What will be the temperature and mass of the gas in the cylinder if this is done?In a manner which maintains the temperature of the gas at 330 K?

User Erki Aring
by
5.0k points

2 Answers

4 votes

Answer:

P1/T1=P2/T2, temperature at 1 atm = 33 K, mass m= density* volume =density*pi*square(radius)*height

Step-by-step explanation:

to maintain the temperature volume at reduced pressure volume will be adjust.

User Eclarkso
by
4.4k points
7 votes

Answer:

See attachment

Step-by-step explanation:

Air in a 10 ft3 cylinder is initially at a pressure of 10 atm and a temperature of-example-1
Air in a 10 ft3 cylinder is initially at a pressure of 10 atm and a temperature of-example-2
Air in a 10 ft3 cylinder is initially at a pressure of 10 atm and a temperature of-example-3
Air in a 10 ft3 cylinder is initially at a pressure of 10 atm and a temperature of-example-4
Air in a 10 ft3 cylinder is initially at a pressure of 10 atm and a temperature of-example-5
User Alon Or
by
5.0k points