Answer:
853776 J
Step-by-step explanation:
The work-energy needs to pump water out of the pool is the product of the weight of water and distance h
E = Wh = mgh
Since water mass is a body of water we can treat it as the product of density 1000kg/m3 and volume, which is the product of base area and uniform height h

Therefore:
![E = mgh = g\rho A\int\limits^(2.2)_0 {h} \, dh\\E = 9.8*1000*30*12[h^2/2]^(2.2)_0 = 1764000(2.2^2 - 0^2) = 853776 J](https://img.qammunity.org/2021/formulas/physics/college/6migp9hhr1hvfg6yuaf14vn7nbfqt0alc2.png)