Question

An 1,840 W toaster, a 1,460 W electric frying pan, and a 50 W lamp are plugged into the same outlet in a 15 A, 120 V circuit. (The three devices are in parallel when plugged into the same socket.) (a) What current (in A) is drawn by each device?

Answer 1

Step-by-step explanation:

power of toaster, P1 = 1840 W

Power of electric frying pan, P2 = 1460 W

Power of lamp, P3 = 50 W

As they all are connected in parallel, so the voltage is same for all.

Let the current in toaster is i1.

P1 = V x i1

1840 = 120 x i1

i1 = 15.33 A

Let the current in frying pan is i2.

P2 = V x i2

1460 = 120 x i1

i1 = 12.17 A

Let the current in lamp is i3.

P3 = V x i3

50 = 120 x i3

i3 = 0.42 A

Answer 2

Step-by-step explanation:

Given

Power drawn by toaster
`P_1=1840\ W`

Power drawn by Electric fan
`P_2=1460\ W`

Power drawn by lamp
`P_3=50\ W`

Voltage applied
`V=120\ V`

If appliances are applied in parallel then Voltage applied is same

Power is given by
`P=(V^2)/(R)`

Resistance of toaster
`R_1=(120^2)/(1840)=7.82\ \Omega`

Resistance of electric Fan
`R_2=(120^2)/(1460)=9.86\ \Omega`

Resistance of toaster
`R_3=(120^2)/(50)=288\ \Omega`

Current is given by

`I=(V)/(R)`

`I_1=(120)/(7.82)=15.34\ A`

`I_2=(120)/(9.86)=12.17\ A`

`I_3=(120)/(288)=0.416\ A`