Question

What is the final velocity of an object that is dropped if it falls a distance of 100 m?

Answer 1

`44.27m/s`

Step-by-step explanation:

The kinematic equation

`v_f^2=v_0^2+2ad`

gives the final velocity
`v_f` of the object given the initial velocity
`v_0`, the acceleration
`a`, and the distance traveled
`d`.

For our case, the object is dropped; therefore,

`v_0=0`

I.e. the initial velocity is zero. The acceleration due to gravity is

`a=9.8m/s^2`,

and the distance traveled is
`d=100m`.

Putting the values into the equation we get:

`v_f^2=0+2(9.8ms^(-2))(100m)\\\\v_f^2=1960\\\\v_f=√(1960) \\\\\boxed{v_f=44.27m/s}`

The final velocity of the object is 44.27 m/s.