Question

How many solutions are there for the quadratic equation?
Y=x^2+12x+36

Show work

Answer 1

`\\ \rm\rightarrowtail x^2+12x+36=0`

`\\ \rm\rightarrowtail x^2+6x+6x+36=0`

`\\ \rm\rightarrowtail (x+6)(x+6)=0`

Only one solution present

x=-6

Answer 2

1 solution

• x = -6

Step-by-step explanation:

`\rightarrow \sf y=x^2+12x+36`

`\rightarrow \sf x^2+12x+36=0`

`\rightarrow \sf x^2+6x+6x+36=0`

`\rightarrow \sf x(x+6)+6(x+6)=0`

`\rightarrow \sf (x+6)(x+6)=0`

`\rightarrow \sf x=-6`

Hence there is only one solution for this quadratic equation and the value is -6