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Please help with this arc equation.

Please help with this arc equation.-example-1
User Nojevive
by
5.4k points

1 Answer

5 votes

Answer:

Part 1)
arc\ AB=49^o

Part 2)
arc\ ABC=204^o

Part 3)
arc\ BAC=156^o

Part 4)
arc\ ACB=311^o

Explanation:

Part 1) Find the measure of arc AB

we know that


arc\ AB=m\angle AOB ----> by central angle

we have


m\angle AOB=49^o

therefore


arc\ AB=49^o

Part 2) Find the measure of arc ABC

we know that

The central angle of complete circle is equal to 360 degrees

so


arc\ ABC=360^o-107^o-49^o=204^o

Part 3) Find the measure of arc BAC

we know that


arc\ BAC=arc\ BA+arc\ AC ----> by angle addition postulate

we have


arc\ BA=49^o ---> by central angle


arc\ AC=107^o ---> by central angle

so


arc\ BAC=49^o+107^o=156^o

Part 4) Find the measure of arc ACB

we know that

The central angle of complete circle is equal to 360 degrees

so


arc\ ACB=360^o-arc\ AB

substitute


arc\ ACB=360^o-49^o=311^o

User Ben Taber
by
5.5k points
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