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The functions f(x) = -2x + 2 and g(x) = (1/3)^x are shown in the graph.

What are the solutions to -2x + 2 = (1/3)^x + 1?
(Multiple choice)

A. -1
B. 0
C. 2
D. 3
E. 4

The functions f(x) = -2x + 2 and g(x) = (1/3)^x are shown in the graph. What are the-example-1
User Himberjack
by
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1 Answer

4 votes

Option a: -1

Option b: 0

Step-by-step explanation:

The function
f(x)=-2 x+2 and
g(x)=\left((1)/(3)\right)^(x)+1

To determine the solution of
-2 x+2=\left((1)/(3)\right)^(x)+1 and solving the expression using lambert's form, we get the solution
x=-1, x=0

Hence, the solution to the functions
f(x)=-2 x+2 and
g(x)=\left((1)/(3)\right)^(x)+1 are -1 and 0.

Also, by looking at the graph, we can see that, the graphs f(x) and g(x) intersect at the points
(-1,4) and
(0,2).

Hence, the solution to
-2 x+2=\left((1)/(3)\right)^(x)+1 is -1 and0.

Thus, Option a and Option b are the correct answers.

User Korrekorre
by
8.3k points

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