Question

A mixture of three gases has a total pressure of 94.5 kpa. if the partial pressure of

the 1st gas is 65.4 kpa and the partial pressure of the 2nd gas is 22.4 kpa, what is the
partial pressure of the 3rd gas of the mixture?

Answer 1

Answer: 6.7 kPa

Step-by-step explanation:

Pressure Total = P(partial 1) + P(partial 2) + P(partial 3) →

94.5 kPa = 65.4 kPa + 22.4 kPa + P(partial 3) →

6.7 = P(partial 3) :)

Answer 2

Given:-

• Partial pressure of 1st gas ,P
  `_1`= 65.4 kpa
• partial pressure of 2nd gas ,P
  `_2`= 22.4 kpa
• Total pressure,P
  `_o` = 94.5 kpa

To Find :-

• partial pressure of the 3rd gas,P
  `_3`

Solution:-

According to the Dalton's law of partial pressures the total pressure exerted by a mixture of gases is equal to the sum of the partial pressures exerted by each individual gas in the mixture.

So, P
`_o` = P
`_1`+ P
`_2`+ P
`_3`

`\longrightarrow`94.5 = 65.4+ 22.4 + P
`_3`

`\longrightarrow`94.5 = 87.8+ P
`_3`

`\longrightarrow` P
`_3` = 94.5 - 87.8

`\longrightarrow`P
`_3` = 6.7 kpa

Therefore, partial pressure of the 3rd gas of the mixture is 6.7 kpa .