Question

Gibson (1986) asked a sample of college students to complete a self-esteem scale on which the midpoint of the scale was the score 108. He found that the average self-esteem score for the samples well above the actual midpoint of the scale. Given that the standard deviation of self esteem scores was 28.15, what would be the score for a sample participant whose ser esteem score was a. 101.67 b. -0.23 c. -0.87 d.0 e. -1.19 f. 0.97

Answer 1

Option B) -0.23

Explanation:

We are given the following information in the question:

Mean, μ = 108

Standard Deviation, σ = 28.15

Formula:

`z_(score) = \displaystyle(x-\mu)/(\sigma)`

We are given x = 101.67

We have to find the corresponding z-score.

Putting values, we get,

`z_(score) = \displaystyle(101.67-108)/(28.15) = -0.2248 \approx -0.23`

Thus, the correct answer is

Option B) -0.23