Answer:
0.854 (85.4%)
Explanation:
Since each bet is independent from others , then for X=gambler’s winnings when she quits
P(X>0) = probability to win in the first bet + probability of losing in the first bet * probability of wining at least one of the 2 additional bets
= 18/38 + (1-18/38) * [18/38*(1-18/38)+(1-18/38)*18/38+18/38*18/38 ] =0.854 (85.4%)