Question

Half of one of the charges is transferred to the other charge and the distance is unchanged. What happens to the force exerted by one charge on the other charge?

Answer 1

3/4F

Step-by-step explanation:

From the relationship between the force between charges and the distance , we have

`F=k(q_(1)q_(2))/(r^(2))\\`

it is obvious from newton law that one force cannot exert more force on the other charge hence the two charges must exert the same force on each other.

If half of he force is transferred to the other charge the new charge values become

`q_(1)=(1)/(2)q\\ q_(2)=(1)/(2)q +q=(3)/(2)q`

if we insert this value into the equation, we arrive at

`F=k(q_(1)q_(2))/(r^(2))\\F=k((1)/(2) q*(3)/(2)q)/(r^(2))\\F=(3)/(4) k(q_(1)q_(2))/(r^(2))\\F_(new) =(3)/(4)F`