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When A and B are mutually exclusive, P(A or B) can be found by adding P(A) and P(B). A. True B. False

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5 votes

Answer:

True

Step-by-step explanation:

We have given that P(A) and P(B) are mutually exclusive

Mutually exclusive means there is no common element in A and B

So
P(A\cap B)=0

We know that
P(A\cup B)=P(A)+P(B)-P(A\cap B)

As A and B are mutually exclusive and so
P(A\cap B)=0

Putting this value in
P(A\cup B)


P(A\cup B)=P(A)+P(B)-0=P(A)+P(B)

From the above equation we can see that
P(A\cup B) is the sum of
P(A) and
P(B)

So the given statement is true statement

User Jooyong
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