Question

When A and B are mutually exclusive, P(A or B) can be found by adding P(A) and P(B). A. True B. False

Answer 1

True

Step-by-step explanation:

We have given that P(A) and P(B) are mutually exclusive

Mutually exclusive means there is no common element in A and B

So
`P(A\cap B)=0`

We know that
`P(A\cup B)=P(A)+P(B)-P(A\cap B)`

As A and B are mutually exclusive and so
`P(A\cap B)=0`

Putting this value in
`P(A\cup B)`

`P(A\cup B)=P(A)+P(B)-0=P(A)+P(B)`

From the above equation we can see that
`P(A\cup B)` is the sum of
`P(A)` and
`P(B)`

So the given statement is true statement