Question

5 1/6 + (7 1/3)l <60

Answer 1

`l<7(21)/(44)`

Explanation:

Given the inequality

`5(1)/(6)+7(1)/(3)l<60`

First, convert mixed numbers to improper fractions:

`5(1)/(6)=(5\cdot 6+1)/(6)=(31)/(6)\\ \\7(1)/(3)=(7\cdot 3+1)/(3)=(22)/(3)`

Now the inequality looks like

`(31)/(6)+(22)/(3)l<60`

Multiply it by 6:

`(31)/(6)\cdot 6+(22)/(3)l\cdot 6<60\cdot 6\\ \\31+44l<360\\ \\44l<360-31\\ \\44l<329\\ \\l<(329)/(44)\\ \\l<7(21)/(44)`