Question

A solution consists of 35.00 g of CuSO4 dissolved in 250.0 mL of water. The molar mass of Cu is 63.55 g/mol the molar mass of S is 32.07 g/mol, and the molar mass of O is 16.00 g/mol. What is the molarity of the solution?

Answer 1

0.87708moldm-3

Step-by-step explanation:

`molar \: mass \: of \: cuso4 = 63.55 + 32.07 + 4(16.00) \\ =159.62gmol {}^( - 1) \\ mole(n) = (mass)/(molar \: mass ) \\ n = (35)/(159.62) \\ n = 0.21927mol \\ molarity = (n)/(v) \\ molarity = (0.21927)/(0.25) \\ molarity = 0.87708moldm {}^( - 3)`