Question

Two uniformly charged conducting plates are parallel to each other. They each have area A. Plate #1 has a positive charge Q while plate #2 has a charge −3 Q.

Using the superposition principle find the magnitude of the electric field at point P in the gap.
1. E =5Q / εoA
2. E = 4Q/εoA
3. E =3Q/ εoA
4. E =Q/ εoA
5. E =2Q/ εoA

Answer 1

Answer:5

Step-by-step explanation:

Given

First Plate has a charge of +Q and area A

Second Plate has a charge of -3 Q and area A

We Know electric Field due to sheet charge is given by

`E=(Q)/(2A\epsilon )`

Where Q=charge over the Plate

A=Area of plate

`\epsilon`= Permittivity of free space

Electric Field Due to Positive charge will always be away from it while for negative charge it is towards it.

Net Electric Field at a point between between the Plates is the superimposition of two electric with direction

`E_(net)=(Q)/(2A\epsilon )+(3Q)/(2A\epsilon )`

`E_(net)=(2Q)/(A\epsilon )`

Net electric Field is towards the negative charged plate