Question

Can someone please help me? It's 1:16am and its due at 7:15am. I've got school.

Answer 1

2 v 13, 2 Square root 13

Explanation:

there's 2 right triangles

a)

10^2 = 6^ + a^2

100 - 36 = a^2

64 = a ^2

a = 8

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now we know the base of the right triangle = 8

and also the base of the left one = 4

8 + 4 = 12

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now find x

b)

x^2 = 6^2 + 4^2

x^2 = 36 + 16

x^2 = 52

x = (square root) 52

x = 2 v 13 <---- "v = square root"

Answer 2

Question :- Find the unknown side .

Instructions :- Simplify the answer if there is square root

Given :-

1. Two triangles
2. Total length of the base 12
3. First triangle dimensions

• 10 as it's hypotenuse
• 6 as it's perpendicular

Answer:- X = ✓ 52 = 7.2

Explanation:-

Formula :-

hypotenuse² = perpendicular²+base²

Solution:-

First triangle:-

`{h}^(2) = {p}^(2) + {b}^(2) \\ {10}^(2) = {6}^(2) + {b}^(2) \\ 100 = 36 + {b}^(2) \\ 100 - 36 = {b}^(2) \\ 64 = {b}^(2) \\ 8 = b`

Second triangle

1. perpendicular = 6
2. hypotenuse = X ( to Find )
3. base = 12-b = 12-8= 4

`{h}^(2) = {p}^(2) + {b}^(2) \\ {x}^(2) = {6}^(2) + {4}^(2) \\ {x}^(2) = 36 + 16 \\ {x}^(2) = 52 \\ x = √(52) = 7.2 \\ x = 7 \: \: approx`