Answer:
Option D is correct.
The force that must be applied to the small cylinder to hold the weight up is 20N
Step-by-step explanation:
For the force to hold the smaller cylinder up, the pressure exerted on/by the pistols must be equal.
Let the pressure on the big cylinder be P₁, the force exerted F₁ = 2kN = 2000N and the area A₁ = 500 cm²
Let the pressure on the small cylinder be P₂, the force exerted F₂ = ? and the area A₂ = 5 cm²
Since the two Areas are in the same units, no need to convert to SI units.
P₁ = P₂
F₁/A₁ = F₂/A₂
2000/500 = F₂/5
F₂ = 2000 × 5/500 = 20N