Question

GOT ANOTHERONE DUE IN 6 MIN PLEASE HELP FAST!!!!!!!!!!!!!!!!!!!!!

Answer 1

✰Given:-

➾Length(L) of bigger rectangle =
`\sf{9+3\: =\:12}`units.

➾Length(l) of smaller rectangle = 9units.

➾Breadth (B) of bigger rectangle =
`\sf{4+4 \:=\: 8}`units.

➾Breadth(b) of smaller rectangle = 4 units.

✰To Find:-

➾Area of the shaded region.

✰Solution:-

➾We can find the area of shaded region by subtracting area of smaller rectangle from area of bigger rectangle(that is whole rectangle including shaded and non shaded region).

So,

➾Area of bigger rectangle =
`\sf{L×B}`(putting the value of L and B from the above given)

=
`\sf{8×12}`

=
`\sf{96unit^2}`

Similarly,

➾Area of smaller rectangle =
`\sf{l×b}`(putting the value of l and b from the above given)

=
`\sf{9×4}`

=
`\sf{36unit^2}`

Now,

➾Area of shaded region = Area of bigger rectangle - Area of smaller rectangle.

`\sf{= 96-36}`

`\sf{= 60unit^2.}`

Therefore, area of shaded region
`\sf{= 60unit^2.}`

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Hope it helps you:)

Answer 2

`\bold{\huge{\underline{ Solution }}}`

Given :-

• We have given one rectangle whose 3 by 4th part is shaded and remaining part is non shaded.

To Find :-

• We have to find the area of shaded region of the given figure .

Let's Begin :-

Here, We have

• The dimensions of large rectangle as 12 units and 8 units
• That is,
• 
  `\sf{ Length = 9 + 3 = 12 \: units}`
• 
  `\sf{ Breath = 4 + 4 = 8 \: units}`
• The dimensions of non shaded rectangles are 9 units and 4 units

We know that,

Area of rectangle

`\bold{\red{ = Length {*} Breath }}`

Subsitute the required values,

Area of large rectangle

`\sf{ = 12 {*} 8 }`

`\sf{ = 96 \:units^(2)}`

Thus, The area of large rectangle is 96 units² .

Now,

Area of non - shaded rectangle

`\sf{ = 9 {*} 4 }`

`\sf{ = 36\: units^(2)}`

Thus, The area of non shaded rectangle is 36 units² .

Therefore,

Area of shaded region

= Area of large rectangle - Area of non shaded rectangle

Subsitute the required values,

`\sf{ = 96 - 36}`

`\sf{ = 60\: units^(2)}`

Hence, The total area of shaded region is 60 sq.units.