Answer:
457.14 Watt
Step-by-step explanation:
The information we have is:
Force:
![F=800N](https://img.qammunity.org/2021/formulas/physics/middle-school/9rmyf9ebere7kqngt6ibzuo6tp2ogqsopo.png)
Distance:
![d=4m](https://img.qammunity.org/2021/formulas/physics/middle-school/zcona695gfqf0nm4jl7vhw8up6pyfzmjx7.png)
Time:
![t=7s](https://img.qammunity.org/2021/formulas/physics/middle-school/cu7iiv347nq5rr8kr7x7je3nu0syggl033.png)
the formula for the power is:
![P=(W)/(t)](https://img.qammunity.org/2021/formulas/physics/middle-school/swt1f3p68iw0jhhdf8c1y7jikqk4hs7tut.png)
where
is work, and
si time.
Also, the formula for work is:
![W=F*d](https://img.qammunity.org/2021/formulas/physics/middle-school/miyg61hjohed0ljxpwosd7yyoy06fx9h2s.png)
Where
is the force, and
is the distance.
Substituting the formula for work into the formula for power:
![W=(F*d)/(t)](https://img.qammunity.org/2021/formulas/physics/middle-school/1hobmddda8h2vxpbgin8ipxls10x6kg0s0.png)
substituting all the values to find the power:
![P=((800N)(4m))/(7s)=(3200Nm)/(7s)\\ P=457.14W](https://img.qammunity.org/2021/formulas/physics/middle-school/840w92hwaudna9249uhlntbf8c8bvxe111.png)
the power that was used is 457.14 Watt