224k views
0 votes
A point charge q1 = -7.7 μC is located at the center of a thick conducting spherical shell of inner radius a = 2.2 cm and outer radius b = 4.5 cm, The conducting spherical shell has a net charge of q2 = 2.6 μC. 1)What is Ex(P), the value of the x-component of the electric field at point P, located a distance 8.8 cm along the x-axis from q1?

User Onknows
by
5.0k points

1 Answer

2 votes

Answer:


E_x = -5.93 * 10^6

Explanation:

Parameters given:

Point charge at the center of the sphere,
q_1 :
-7.7 * 10^(-6)μC

Charge of the sphere,
q_2 :
2.6 * 10^(-6)μC

Distance between
q_1 and the point of consideration =
8.8 * 10^(-2) m

Distance between
q_2 and the point of consideration =
8.8 * 10^(-2) m

Electric field is given as


E_x = (kq)/(r^2)

where

k = Coulombs constant;

q = electric charge;

r = distance between charge and point of consideration.

The net electric field at that point is the sum of the electric field due to
q_1 and
q_2, i.e.:


E_x = (kq_1)/(r^2) + (kq_2)/(r^2)

Since k is the same and the distance, r is also the same, then:


E_x =(k)/(r^2) ( q_1 + q_2)

=>
E_x =(9 * 10^9)/((8.8 * 10^(-2))^2) [ (-7.7 * 10^(-6)) + (2.6 * 10^(-6))]

=>
E_x = 1.162 * 10^(12) * -5.1 * 10^(-6)\\\\\\E_x = -5.93 * 10^6

The electric field along the x axis,
E_x = -5.93 * 10^6

User Dimitar Tsonev
by
4.7k points