Answer:
![E_x = -5.93 * 10^6](https://img.qammunity.org/2021/formulas/mathematics/college/ym4sa4cbqoc18akfpfe8cs2w4csjbc0u76.png)
Explanation:
Parameters given:
Point charge at the center of the sphere,
:
μC
Charge of the sphere,
:
μC
Distance between
and the point of consideration =
![8.8 * 10^(-2) m](https://img.qammunity.org/2021/formulas/mathematics/college/785knonkfz575keyjmls5a8hnk4rrnqxgw.png)
Distance between
and the point of consideration =
![8.8 * 10^(-2) m](https://img.qammunity.org/2021/formulas/mathematics/college/785knonkfz575keyjmls5a8hnk4rrnqxgw.png)
Electric field is given as
![E_x = (kq)/(r^2)](https://img.qammunity.org/2021/formulas/mathematics/college/25lil57n94n8wwv82xcs3am3kpgnuz8n27.png)
where
k = Coulombs constant;
q = electric charge;
r = distance between charge and point of consideration.
The net electric field at that point is the sum of the electric field due to
and
, i.e.:
![E_x = (kq_1)/(r^2) + (kq_2)/(r^2)](https://img.qammunity.org/2021/formulas/mathematics/college/6561h871iuh7z2gw2nczuy9o3ymd786bx7.png)
Since k is the same and the distance, r is also the same, then:
![E_x =(k)/(r^2) ( q_1 + q_2)](https://img.qammunity.org/2021/formulas/mathematics/college/x261kbfof429ivuhdrhnu3aw8spaal2vau.png)
=>
![E_x =(9 * 10^9)/((8.8 * 10^(-2))^2) [ (-7.7 * 10^(-6)) + (2.6 * 10^(-6))]](https://img.qammunity.org/2021/formulas/mathematics/college/3foiv4yhag4nj8i3zjd3cfch0102ia2rcu.png)
=>
![E_x = 1.162 * 10^(12) * -5.1 * 10^(-6)\\\\\\E_x = -5.93 * 10^6](https://img.qammunity.org/2021/formulas/mathematics/college/1z8zn54ku0rswkx9ervzncg8j44q67hnw1.png)
The electric field along the x axis,
![E_x = -5.93 * 10^6](https://img.qammunity.org/2021/formulas/mathematics/college/ym4sa4cbqoc18akfpfe8cs2w4csjbc0u76.png)