Question

How many moles of neon gas are there 25.0 L of gas or 5.0°C with a pressure of 89.9 KPa?

Answer 1

• Volume=25L
• Temperature=5°C
• Pressure=89.9kPa

Now

`\\ \rm\rightarrowtail PV=nRT`

`\\ \rm\rightarrowtail n=(PV)/(RT)`

`\\ \rm\rightarrowtail n=(89.9(25))/(5R)`

`\\ \rm\rightarrowtail n=89.9(5)/R`

`\\ \rm\rightarrowtail n=449.5/R mol`