Answer:
Options B and C are correct choices.
Explanation:
We have been given 4 pairs of ratios. We are asked to choose the pairs that form a proportion.
We know that two quantities are proportional if their ratios are same.
Let us check our each pair.
A. One sixth and four over twenty.
Express as fractions and equate:
![(1)/(6)=(4)/(20)](https://img.qammunity.org/2021/formulas/mathematics/high-school/ynmdnnjkyfngeguarordzohzrbpt8ocyb1.png)
![(1)/(6)=(4\cdot 1)/(4\cdot 5)\\\\(1)/(6)\\eq (1)/(5)](https://img.qammunity.org/2021/formulas/mathematics/high-school/34zu8c3nl4mpwo2tes8anwka68nesrxtsw.png)
Since ratio is not same, therefore, this pair is not proportional.
B. Seven ninths and twenty eight over thirty six.
Express as fractions and equate:
![(7)/(9)=(28)/(36)\\\\(7)/(9)=(4\cdot 7)/(4\cdot 9)\\\\(7)/(9)=(7)/(9)](https://img.qammunity.org/2021/formulas/mathematics/high-school/g3t21n0bl3n7le60v0diiqmc0f55md1o6r.png)
Since ratio is same, therefore, this pair is proportional.
C. Fourteen over eighteen and twenty one over twenty seven.
Express as fractions and equate:
![(14)/(18)=(21)/(27)\\\\(2\cdot 7)/(2\cdot 9)=(3\cdot 7)/(3\cdot 9)\\\\(7)/(9)=(7)/(9)](https://img.qammunity.org/2021/formulas/mathematics/high-school/d3myaa4lkfn378r0ypm0erewsxl7dt8by8.png)
Since ratio is same, therefore, this pair is proportional.
C. Thirty over eighty and six over eighteen.
Express as fractions and equate:
![(30)/(80)=(6)/(18)\\\\(10\cdot 3)/(10\cdot 8)=(6\cdot 1)/(6\cdot 3)\\\\(3)/(8)\\eq (1)/(3)](https://img.qammunity.org/2021/formulas/mathematics/high-school/ouzcjyozwr1n11qnybi45hwwl5ti38qnxf.png)
Since ratio is not same, therefore, this pair is not proportional.