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A circle is shown. A secant and a tangent intersect at a common point outside of the circle to form an angle that measure 51 degrees. The measure of the first arc formed is x degrees and the measure of the second arc formed is 160 degrees. What is the value of x? x =

A circle is shown. A secant and a tangent intersect at a common point outside of the-example-1

2 Answers

4 votes

Answer:

58

Explanation:

User Esben Bach
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5 votes

The value of x is 58°.

Solution:

The measure of the first arc formed = x°

The measure of the second arc formed = 160°

Angle formed between tangent and secant = 51°

Theorem:

If a secant and a tangent intersect at a common point in the exterior of a circle, then the measure of the angle formed is the half the difference of the measures of the intercepted arcs.


$\Rightarrow 51^(\circ)=(1)/(2)(160^(\circ) -x^(\circ))

Multiply by 2 on both sides of the equation.


$\Rightarrow 51^(\circ)* 2=2*(1)/(2)(160^(\circ) -x^(\circ))


$\Rightarrow 102^(\circ)=160^(\circ) -x^(\circ)

Subtract 160° on both sides of the equation.


$\Rightarrow 102^(\circ)-160^(\circ)=160^(\circ) -x^(\circ)-160^(\circ)


$\Rightarrow -58^(\circ)=-x^(\circ)

Multiply by (–1) on both sides of the equation.


$\Rightarrow -58^(\circ)*(-1)=-x^(\circ)*(-1)


$\Rightarrow x^(\circ)=58^(\circ)

Hence the value of x is 58°.

User Gbroekstg
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