Answer:
The mass of the asteroids is 0.000334896182184 times the mass of the Earth.
39929.4542466 m
Step-by-step explanation:
Total mass of the asteroids
![m_a20000* 10^(17)=2* 10^(21)\ kg](https://img.qammunity.org/2021/formulas/physics/college/y31xgsry87kqgh5tl9n2pi53xpastr8fpa.png)
= Mass of Earth =
![5.972* 10^(24)\ kg](https://img.qammunity.org/2021/formulas/physics/college/e70wo0dv0iwa1vwp5csd8hniunyyrg9pbg.png)
The ratio is
![(m_a)/(m_e)=(2* 10^(21))/(5.972* 10^(24))\\\Rightarrow (m_a)/(m_e)=0.000334896182184](https://img.qammunity.org/2021/formulas/physics/college/5y5n1g4ics7ivqq7kgiwiikiweqt7umqlq.png)
The mass of the asteroids is 0.000334896182184 times the mass of the Earth.
Volume is given by
![V=(m)/(\rho)\\\Rightarrow (4\pi)/(3* 8) d^3=(m)/(\rho)\\\Rightarrow d^3=(3* 8)/(4\pi)(m)/(\rho)\\\Rightarrow d=((3* 8)/(4\pi)(m)/(\rho))^{(1)/(3)}\\\Rightarrow d=((3* 8)/(4\pi)(10^(17))/(3000))^{(1)/(3)}\\\Rightarrow d=39929.4542466\ m](https://img.qammunity.org/2021/formulas/physics/college/tnl010k1yyhpwe6yeckd66qqvxx59ho8cu.png)
The diameter is 39929.4542466 m