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an assembly operation at a furniture factory, six employees assembled an average of 450 standard dining chairs per five- ay week. What is the labor productivity of this operation? a. 90 chairs/worker/day b. 75 chairs/worker/day c. 60 chairs/worker/day d. 15 chairs/worker/day e. 20 chairs/worker/day

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Answer:

d. 15 chairs/worker/day

Step-by-step explanation:

Given that

Average of standard dining chairs = 450

Number of employees = 6

Number of days in a week = 5

So, The formula and the computation of the labor productivity of this operation is presented below:

Labor Productivity = Output ÷ Labor Input

where,

Output = 450 standard dining chairs

Labor output = 6 employees × 5 days in a week = 30

So, labor productivity is

= 450 ÷ 30

= 15 chairs per worker per day

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