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Five vials each contain 12 grams of a solid metal sample. The samples include calcium, platinum, barium, gold, and silver. Which vial has the fewest moles of metal atoms?a. Calcium b. Barium c. Gold d. Silver e. Platinum.

1 Answer

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Answer: option c. Gold

Step-by-step explanation:

Mass of calcium = 12g

Molar Mass of calcium =40g/mol

n = Mass / Molar Mass = 12/40 = 0.3mol

Mass of platinum = 12g

Molar Mass of platinum = 195g/mol

n = Mass / Molar Mass = 12/195 = 0.062mol

Mass of Barium = 12g

Molar Mass of Barium = 137g/mol

n = Mass / Molar Mass = 12/137 = 0.088mol

Mass of Gold = 12g

Molar Mass of Gold = 197g/mol

n = Mass / Molar Mass = 12/197 = 0.061mol

Mass of silver = 12g

Molar Mass of silver = 108g/mol

n = Mass / Molar Mass = 12/108 = 0.111mol

From the above, gold has the lowest number of mol i.e 0.061mol

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