Answer:
Minimum quantity = q = 70.71units
Explanation:
Give c(q)= 75+2q+0.015q^2
but average cost A(q) = c(q)/q
A(q) = 75/q + 2 + 0.015q
for minimum cost, differentiate A (q) wrt q
= -75/q2 + 0.015 = 0
q2 = 5000
q = 70.71units
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